(x^2+3x-4)/(x^2-16)=0

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Solution for (x^2+3x-4)/(x^2-16)=0 equation: 


D( x )

x^2-16 = 0

x^2-16 = 0

x^2-16 = 0

1*x^2 = 16 // : 1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in (-oo:-4) U (-4:4) U (4:+oo)

(x^2+3*x-4)/(x^2-16) = 0

x^2+3*x-4 = 0

x^2+3*x-4 = 0

DELTA = 3^2-(-4*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)-3)/(1*2) or x = (-25^(1/2)-3)/(1*2)

x = 1 or x = -4

(x+4)*(x-1) = 0

((x+4)*(x-1))/(x^2-16) = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -4} 

x = 1

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